Question

find the largest no.that divides 2053 and 967 leaves remainder 5 and 7 respectively

Answer 1

It is given that on dividing 2053 by the required number there is a remainder of 5 .
this mean that 2053 - 5 = 2048 is exactly divisible by required number . similarly,967 - 7 = 960the required number is the largest number satisfying the above property .therefore ,it is the HCF of 2048 & 960HCF of 2048 & 960 is 64 hence required number is 64