find the largest no. which divides 248 and 1032 leaving remainder 8 in each case
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for x is the factor of 248 - 8= 240 and 1032 - 8 = 1024 now take the lcm of their products 240= 2.2.2.2.3.5 and 1024=2.2.2.2.2.2.2.2.2.2 hcf = 2.2.2.2=16 therefore 16 is the largest positive integer which divides 248 and 1032 leaving remainder 8 in each case.
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