Find the largest no. Which divides 320 and 457 leaving remainders 5 and 7 respectively
Answers
Answered by
3
hey mate!!
for finding the largest number,first we need to subtract 5 and 7 from 320 and 457 respectively
so, 320-5=315
and 457-7=450
now, we need to find the HCF
by prime factorisation
315=3*3*5*7
450=2*3*3*5*5
HCF of 315 and 450=3*5=15
thus the largest which divides 320 and 457 leaving remainders 5 and 7 respectively is 15
hope it helped!!
for finding the largest number,first we need to subtract 5 and 7 from 320 and 457 respectively
so, 320-5=315
and 457-7=450
now, we need to find the HCF
by prime factorisation
315=3*3*5*7
450=2*3*3*5*5
HCF of 315 and 450=3*5=15
thus the largest which divides 320 and 457 leaving remainders 5 and 7 respectively is 15
hope it helped!!
Similar questions