FIND THE LARGEST NO. WHICH DIVIDES 382 AND 508 LEAVING REMAINDER 4 IN EACH CASE
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for leaving remainder 4 in each case we subtract 4 from 382 and 508
382-4 = 378
508-4= 504
hcf of 378 and 504 = 126
so the number which divides 382 and 508 leaving remainder 4 in each case is 126
382-4 = 378
508-4= 504
hcf of 378 and 504 = 126
so the number which divides 382 and 508 leaving remainder 4 in each case is 126
chopramonika:
7 TH
me too
which class u are
7th
WHICH SCHOOL IN U ARE
Kendriya Vidyalaya
and u
BAL BHARATI PUBLIC SCHOOL
IN WHICH SEC
SEC 14
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IN WHICH SCHOOL IN U ARE
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