Question

Find the largest no. which divides 438 &606 leaving remainders 6 in each case

Answer 1

• (438-6)= 432.....................(1)

• (606-6)=600.......................(2)

By taking LCM Both the equation 1 & 2

432=2⁴*3³...................................(3)

600=2³*3*5................................(4)

Now  we take the HCF

HCf(common No. on both equation (3) &(4))

=2³*3

=8*3

=24

HCF=24

Answer 2

hcf=35

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