Question

Find the largest no. which divides 699 ,572 and 445 leaving remainders 6, 5 and 4 respectively

Answer 1

The number will completely divides (699-6),(572-5)and (445-4) leaving no remainder.
The largest number will be HCF of 693, 567 and 441
693 = 3×3×7×11
567=3×3×3×3×7
441 = 3×3×7×7

HCF = 3×3×7 = 63

Required number = 63