find the largest no which leaves remainder 4 and 6 respectively when it divides 220and186
Answers
Answered by
1
Answer:
your answer is 36
Step-by-step explanation:
220-4 = 216
186-6 = 180
HCF:-
smallest 180
greatest 216
216÷180 = divisor 1 , remainder 36
180÷36 = divisor 5 , remainder 0
HCF is 36 Ans
Answered by
0
Answer:
The number leaves remainder 4 and 6 respectively when it divides 220 and 186
So the required number is HCF of
(220-4) & (186 -6)
That is 216 & 180
So the required answer is = 36
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