Find the largest no.which when divide 1485 and 940 leave a remainders 3 and 4 as a respectively
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Answer:
1st step
1485-3=1482
940-4=936
now we find hcf of 1482 and 936
1482÷936=quotient 1 remainder 576
936÷576=quotient 1 remainder 360
576÷360=quotient 1 r 216
360÷216=q 1 r 144
216÷144=q 1 r 72
144÷72=2
required largest no 72
that divides 1485 and 940 leave as remainder 3 and 4
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