Find the largest number apart from 840 that is a multiple of 24 and a factor of 840
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Answered by
9
Answer:
the answer is 168
Step-by-step explanation:
split 840 and 24 into primes
840 = 2×2×2×3x5x7
24= 2x2x2x3
therefore, any multiple of 24 must have those factor
so, factors of 840 that are multiples of 24 are
2x2x2x3 = 24
2x2x2x3x5 =120
2x2x2x3x7 = 168
2x2x2x5x7 = 840
Hence, proved
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Answered by
1
Answer: 168
Step-by-step explanation:
first, split both 840 and 24 into there primes.
840=2×2×2×3×5×7
24=2×2×2×3
therefore any multiples of 24 must have those factor.
so, factors of 840 that are multiples of 24 are
2×2×2×3=24 2×2×2×3×5=120 2×2×2×3×7=168
2×2×2×3×5×7=840
there the answer is 168
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