Question

Find the largest number by which divided by 21 30 and 48 is left 3 remainder?​

Answer 1

Answer:

let first minus 3 from other three number

21==>21-3=18

30==>30-3=27

48==>48-3=45

prime factorize all these no.

18=2×3×3

27=3×3×3

45=5×3×3

taking HCF (taking common among all)

we get

3×3=9

hence 9 is the largest number which divide 21, 30. and 48 and left the remainder 3.

hope this will help........

♥️♥️♥️plz mark as brainliest ♥️♥️♥️