Math, asked by nerdysmridhi, 1 year ago

Find the largest number not exceeding 800 which when divided by 15, 18 or 24 leaves the remaider 3 in each case

Answers

Answered by faizzayn
0
First find the least number that can be divisible by 15,18&24.For that, we have to find L.C.M of 15,18&24
L.C.M = 360
Largest number divisible by 15,18&24 which should not exceed 800= 800-80
=720
360)800(2
720
---------
80
Therefore,largest number not exceeding 800 which when divided by by 15,18&24 leaves the remainder 3 in each case = 720+3 =723 ...
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