find the largest number of 2 digits which is a perfect square
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Square of 10 = 100 > 99 thus number would be less than 10. Since we are asking for 2 digit number which is an integer then we consider only whole numbers thus, largest whole number less than 10 is 9. 9^2 = 81. Hence largest two digit number who is also a perfect square = 81.
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Answer:
81 is the answer of the question
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