Find the largest number of 3 digits which is a perfect square
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12
30×30=900
31×31=961
32×32=1024
Therefore
961 is largest 3 digit number which is a perfect square
961=(31)^2
31×31=961
32×32=1024
Therefore
961 is largest 3 digit number which is a perfect square
961=(31)^2
Answered by
0
6 ] = ] Three digits no is 999 .
= ] 12 x 12 = 144 .
= ] 13 x 13 = 169 .
= ] 20 x 20 = 400 .
= ] 30 x 30 = 900 .
= ] 31 x 31 = 961 .
Step-by-step explanation:
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