Find the largest number of 4-digits divisible by 12, 15 and 18. *
i want ans in explained form plz.
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Answered by
1
Answer:
Step-by-step explanation:
9900
Step-by-step explanation:
LCM of 12,15,18 = 180
largest 4 digit no. = 9999
Now divide 9999 by 180 and subtract the remainder
9999/180 , remainder 99
NO. = 9999 - 99 = 9900
Answered by
0
Step-by-step explanation:
The largest number of four digits is 9999.
Required number must be divisible by L.C.M of 12,15,18,27 i.e., 540.
On dividing 9999 by 540, we get 279 as remainder.
∴ Required number=(9999−279)=9720.
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