find the largest number of 4 digits divisible by 12,15and 18
Answers
Answered by
1
Step-by-step explanation:
The largest number of four digits is 9999.
Required number must be divisible by L.C.M of 12,15,18,27 i.e., 540.
On dividing 9999 by 540, we get 279 as remainder.
∴ Required number=(9999−279)=9720.
Answered by
0
Answer:
the largest 4 digit no.divisible by 12,15,18 is 9720
Similar questions
Math,
2 months ago
Accountancy,
2 months ago
History,
5 months ago
Psychology,
5 months ago
Math,
10 months ago
Math,
10 months ago
Math,
10 months ago