Math, asked by muniprasad8630, 5 months ago

find the largest number of 4 digits divisible by 12,15and 18​

Answers

Answered by jasbirsingh56789
1

Step-by-step explanation:

The largest number of four digits is 9999.

Required number must be divisible by L.C.M of 12,15,18,27 i.e., 540.

On dividing 9999 by 540, we get 279 as remainder.

∴ Required number=(9999−279)=9720.

Answered by abhipsa0015
0

Answer:

the largest 4 digit no.divisible by 12,15,18 is 9720

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