Math, asked by Harden, 1 year ago

find the largest number of 4 digits exactly divisible by 12, 15, 18, and 27

Answers

Answered by Darkhawk
49
The Largest number of four digits is 9999. Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540. On dividing 9999 by 540,we get 279 as remainder . \Required number = (9999-279) = 9720

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