find the largest number of 4 digits exactly divisible by 12, 15, 18, and 27
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The Largest number of four digits is 9999. Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540. On dividing 9999 by 540,we get 279 as remainder . \Required number = (9999-279) = 9720
Hope it helps....
Hope it helps....
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