find the largest number of 4 digits such that on dividing by 15 18 and 21 the remainders
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15 = 3 * 5
18 = 3^2 * 2
21 = 3 *7
24 = 2^3 * 3
L.C.M = 8 * 9 * 5 * 7 = 2520
The largest number of four digits = 9999/2520
Required number = 9999 - 2439-4 = 7556.
Hope it Will help.
18 = 3^2 * 2
21 = 3 *7
24 = 2^3 * 3
L.C.M = 8 * 9 * 5 * 7 = 2520
The largest number of four digits = 9999/2520
Required number = 9999 - 2439-4 = 7556.
Hope it Will help.
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