find the largest number of children who can share equally 126 oranges and 147 bananas.
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3
147 children has large
Answered by
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Factors of 126 = 1,2,3,6,9,14,21,42,63,126
Factors of 147 = 1,3,7,21,49,147
HCF = 21
Therefore,
Maximum number of children who can share equally are 21.
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