Question

Find the largest number of four-digits which when divided by 9,12,24 and 45leaves a remainder 5 in each case.
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Answer 1

Answer:

3965

Step-by-step explanation:

1. To find a 4-digit number that leaves 5 as remainder on getting divided by 9,12,24 and 45 we will find its L.C.M. that is 360.
2. Now the greatest multiple of 360 in a 4-digit form is 3960.
3. Also, as mentioned in the question, we need a remainder of 5,
4. Thus, we will add 5 to 3960.
5. 3960 + 5 = 3965
6. Thus 3965 is the largest number of four-digits which when divided by 9,12,24 and 45 leaves a remainder 5 in each case.

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Answer 2

Step-by-step explanation:

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