Question

find the largest number of two digits, exactly divisable by 2,4,6,8 and 16​

Answer 1

Answer:

Lowest among 3 digits number=100, which is divisible by 4 and quotient is 25. So largest 2 digit number divisible by 4 must have quotient 24, and the number is 24×4=96

For 6, 100/6 , quotient 16, remainder 4. Here the largest 2 digit number = 100–4=96

For ,8, 100/8, quotient 12, remainder again 4, in this case also largest 2 digit number divisible by 8 = 100–4=96

For 12, 100/12, quotient =8 , remainder again 4.Again largest 2 digit number divisible by 12= 100–4=96.

So largest 2 digit number divisible by 4, 6,8,12 is 96

Answer 2

★QUESTION★

What is the largest 2-digit number divisible by 4, 6, 8, and 12?

★ANSWER★

★96★

★SOLUTION★

Lowest among 3 digits number=100, which is divisible by 4 and quotient is 25.

So largest 2 digit number divisible by 4 must have quotient 24, and the number is 24×4=96For 6, 100/6 , quotient 16, remainder 4.

Here the largest 2 digit number = 100–4=96For ,8, 100/8, quotient 12, remainder again 4, in this case also largest 2 digit number divisible by 8 = 100–4=96For 12, 100/12, quotient =8 , remainder again 4.

Again largest 2 digit number divisible by 12= 100–4=96.So largest 2 digit number divisible by 4, 6,8,12 is 96

★HOPE IT HELPS★

★BRAINLIEST PLZ★