Question

Find the largest number that divides 187, 259, and 281 leaving remainder 7,9and11 respectively

Answer 1

187-7=180
259-9=250
281-11=270
Required no is HCF of 180, 250, 270
180=2×2×3×3×5
250=2×5×5×5
270=2×3×3×3×5
HCF=2×5=10
10 is the required no which on dividing 187,259,281 leave remainder 7,9,11 respectively.