find the largest number that divides 2053 and 967 and leaves remainder of 5 and 7 respectively
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Answered by
59
2053-5=2048
967-7=960
H.C.F of 2048 and 967=2*2*2*2*2*2=64
967-7=960
H.C.F of 2048 and 967=2*2*2*2*2*2=64
Answered by
63
If 2053 - 5 = 2048
967 - 7 = 960
HCF of 2048 and 960 is 64.
So the largest no is 64.
967 - 7 = 960
HCF of 2048 and 960 is 64.
So the largest no is 64.
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