Find the largest number that divides 2053 and 967
and leaves as remainder of 5 and 7 respectively.
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Answered by
8
it is given that on dividing 2053 by the required number there is a remainder of 5 .this mean that 2053 - 5 = 2048 is exactly divisible by required number . similarly,
967 - 7 = 960
the required number is the largest number satisfying the above property .
therefore ,it is the HCF of 2048 & 960
HCF of 2048 & 960 is 64
hence required number is 64
Answered by
0
Simply subtract 5 from 2053 and 7 from 967 and then find hcf of those 2
=> hcf(2048,960) => 64
=> hcf(2048,960) => 64
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