Question

find the largest number that divides 2053 and 967 and leaves a remainder of 5 and 7 respectively



only simple answer​

Answer 1

Answer:

2053−5=2048

967−7=960

Prime factors of 2048=2×2×2×2×2×2×2×2×2×2

Prime factors of 960=2×2×2×2×2×2×3×5

HCF of 2048 and 960=2×2×2×2×2×2=64

Step-by-step explanation:

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Answer 2

Hence, number N is 64 which will give remainders 5 and 7 on dividing 2053 and 967 respectively.

$7 + 2 + 3x {wrong formula}$