find the largest number that divides 2053 and 967 and leaves a remainder of 5 and 7 respectively.
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it is given that on dividing 2053 by the required number there is a remainder of 5 .
this mean that 2053 - 5 = 2048 is exactly divisible by required number. similarly,
967 - 7 = 960
the required number is the largest number satisfying the above property.
therefore, it is the HCF of 2048 & 960
HCF of 2048 & 960 is 64 hence required number is 64
Alternate Method :
2053-5=2048
967-7=960
take the hcf ( 2048,960)
ans=64
Hope This Helps :)
this mean that 2053 - 5 = 2048 is exactly divisible by required number. similarly,
967 - 7 = 960
the required number is the largest number satisfying the above property.
therefore, it is the HCF of 2048 & 960
HCF of 2048 & 960 is 64 hence required number is 64
Alternate Method :
2053-5=2048
967-7=960
take the hcf ( 2048,960)
ans=64
Hope This Helps :)
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