find the largest number that divides 2053 and 967 and leaves a remainder of 5 and 7
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Secondary SchoolMath5 points
Find the largest number that will divide 2053 and 967 and leaves a remainder of 5 and 7 respectively.
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Ask for details FollowReport by Srishtu21.05.2014
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THE BRAINLIEST ANSWER!

It is given that on dividing 2053 by the required number there is a remainder of 5 .this mean that 2053 - 5 = 2048 is exactly divisible by required number . similarly,
967 - 7 = 960
the required number is the largest number satisfying the above property .
therefore ,it is the HCF of 2048 & 960
HCF of 2048 & 960 is 64
hence required number is 64
Secondary SchoolMath5 points
Find the largest number that will divide 2053 and 967 and leaves a remainder of 5 and 7 respectively.
Advertisement
Ask for details FollowReport by Srishtu21.05.2014
Answers
THE BRAINLIEST ANSWER!

It is given that on dividing 2053 by the required number there is a remainder of 5 .this mean that 2053 - 5 = 2048 is exactly divisible by required number . similarly,
967 - 7 = 960
the required number is the largest number satisfying the above property .
therefore ,it is the HCF of 2048 & 960
HCF of 2048 & 960 is 64
hence required number is 64
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