find the largest number that divides 2057 and 967 and leaves remainder 5 and 7 respectively
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Step-by-step explanation:
2053 - 5 = 2048 and 967 - 7 = 960.
Prime factorisation of 2048 and 960 are as follows,
2048 = 211 and 960 = 26 × 3 × 5.
HCF(2048, 960) = 26 =64.
Therefore, the largest number which divides 2053 and 967 and leaves remainder 5 and 7 respectively is 64.
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