Question

Find the largest number that divides 220,313, and 716 leaving remainder 3 in each cases

Answer 1

Answer:

First we will subtract 3 from each no.-

220 - 3 = 217

313 - 3 = 310

716 - 3 = 713

Then,

we will find the HCF of 217,310,713 217 = 7×31 310

= 2×5×31 713 = 23×31.

So,

the HCF of 217,310,713 is 31.

So, therefore, the largest no.

that divides 220,313,

and 716 is 31.

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Answer 2

Answer is 3....

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Question :-

Find the largest number that divides 220,313, and 716 leaving remainder 3 in each cases

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To Find :-

H.C.F of 210 , 313 and 716

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Solution :-

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By prime factorizing of 217, 310 and 713 we get..

$\implies \bf \: 220 - 3 = 217$

$\implies \bf \: 313 - 3 = 310$

$\implies \bf \: 716 - 3 = 713$

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By prime factorizing of 217, 310 and 713 we get

$\implies\bf \: 217 = 7 \times 31$

$\implies\bf \: 310 = 2 \times 5 \times 31$

$\implies\bf \: 713 = 23\times 31$

$\bold{\red{So \: , \: the \: \: H.C.F \: \: is \: \: 31 ...}}$

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Learn More :-

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How to find H.C.F And L.C.M....

Put the given numbers inside the L shape

We have to split the given number by prime numbers only. That is, always we have to put prime numbers out side the L shape.

Given below will be helpful to find the prime number which exactly divides the given number.

• A number which ends with 0, 2, 4, 6 and 8 is divisible by the smallest prime number 2.
• A number which ends with 0 or 5 is divisible by 5
• If the sum of digits of the given number is a multiple of 3, then the given number is divisible by 3.

Repeat this process until get prime numbers inside the ladder.

The product of numbers out side the ladder will be the HCF...

The product of numbers inside and out side the ladder will be the LCM...

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