Question

find the largest number that divides 31 and 99 leaving remainder 5 and8​

Answer 1

31-5 = 26

99-8 = 91

therfore, prime factorisation of 26 = 2 x 13-(1)

and 91 = 7 x 13-(2)

HCF will be the largest number that divides 31 and 99 to leave remainder 5 and 8 respectively .

therefore HCF= 13 -(from 1 and 2 )