Question

find the largest number that divides 398 436 and 542 leaving remainders 7 11 and 15 respectively​

Answer 1

398 - 7 = 391

436 - 11 = 425

542 - 15 = 527

For answer we need to take hcf of 391, 425, and 527

hcf = 17

Hence required no. 17

Answer 2

Given :-

398 , 436 and 542

To Find :-

The largest number

Solution :-

Let’s assume the integer is x

According to the condition given in the question

⇒ xy+7 = 398

⇒  xz+11 = 436

⇒  xk+15 = 542

⇒ xy =391

⇒  xz = 425

⇒  xk = 527

⇒  17 × 23 = 391

⇒  17 × 25 = 425

⇒ 17 × 31 = 527

So, the largest possible integer that will divide 398,436,542 & leaves reminder 7,11 and 15 respectively was 17.