Find the largest number that divides 398, 436 and 542 leaving remainders 7, 11 and 15 respectively
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Answer:
17
Step-by-step explanation:
First, subtract the remainders from the respective numbers/
398 - 7 = 391
436 - 11 = 425
542 - 15 = 527
Represent the numbers in the form of prime factorization
391 = 17 x 23
425 = 5 x 5 x 17
527 = 17 x 31
In these equations, 17 is common in all three.
Hence 17 is the HCF (or largest number)
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