Math, asked by shreyansh160203, 7 hours ago

Find the largest number that divides 398, 436 and 542 leaving remainders 7, 11 and 15 respectively ​

Answers

Answered by Styxoid
1

Answer:

17

Step-by-step explanation:

First, subtract the remainders from the respective numbers/

398 - 7 = 391

436 - 11 = 425

542 - 15 = 527

Represent the numbers in the form of prime factorization

391 = 17 x 23

425 = 5 x 5 x 17

527 = 17 x 31

In these equations, 17 is common in all three.

Hence 17 is the HCF (or largest number)

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