Question

Find the largest number that divides 398,436and 542 leaving remainders 7,11&15

Answer 1

Answer:

Hi

SOLUTION :-

here,

N1 = 398-7 = 391 ( eq 1 )

N2 = 436-11 = 425 ( eq 2 )

N3 = 542-15 =527 ( eq 3 )

Now,

prime factorisation for each EQ

N1 = 23×17

N2 = 17×5×5

N3 = 31×17

• HCF = 17

Largest number =17

HOPE IT HELPS YOU!!!!