Math, asked by Digenbora, 11 months ago

Find the largest number that divides 628, 3129 and 15630 to leave remainders 3,4,5 respectively

Answers

Answered by preranaupadhyay742
3

Answer:

625 is your answer

Step-by-step explanation:

for x is the factor of                                                                     = 628-3= 625                                                                              =3129-4=3125                                                                           =15630-5=15625                                                                 therefore625=5.5.5.5

=3125= 5.5.5.5.5 and                                                           =15625=5.5.5.5.5.5.( hcf= 625)

therefore 625 is largest number.


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Answered by sushugenius
12

628, 3129, and 15630

628-3=625

3129-4=3125

15630-5=15625

As 15625 and 3125 are largest number among them So,

15625=3125×5+0

H.C.F.=3125

Now, Find H.C.F. of 3125 and 625,

3125=625×5=0

H.C.F.=625.

H.C.F.(625, 3125, 15625)=625

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