Find the largest number that divides 628, 3129 and 15630 to leave remainders 3,4,5 respectively
Answers
Answer:
625 is your answer
Step-by-step explanation:
for x is the factor of = 628-3= 625 =3129-4=3125 =15630-5=15625 therefore625=5.5.5.5
=3125= 5.5.5.5.5 and =15625=5.5.5.5.5.5.( hcf= 625)
therefore 625 is largest number.
628, 3129, and 15630
628-3=625
3129-4=3125
15630-5=15625
As 15625 and 3125 are largest number among them So,
15625=3125×5+0
H.C.F.=3125
Now, Find H.C.F. of 3125 and 625,
3125=625×5=0
H.C.F.=625.
H.C.F.(625, 3125, 15625)=625
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