Question

Find the largest number that divides 997,889 and 1111 leaving 7,9,11 as remainder respectively​

Answer 1

Answer:

110  

Step-by-step explanation:

let the number be x

as 997/x leaves a remainder of 7,

997-7/x will not leave a remainder

990/x leaves no remainder

889/x leaves 9 as remainder

889-9/x leaves no remainder

880/x leaves no remainder

1111/x leaves 11 as remainder

1111-11/x leaves no remainder

1100/x leaves no remainder

a number which divides 990, 880 and 1100 completely is the HCF of the numbers

990=2*3*3*5*11

880=2*2*2*2*5*11

1100=2*2*5*5*11

so, HCF(990,880,1100)=2*5*11

=110

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