find the largest number that will divide 112,150 and 115 leaving remainders 5,7,11 respectively
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Step-by-step explanation:
112 - 5 = 107
150 - 7 = 143
115 - 11 = 104
HCF ( 107 , 143, 104 ) = largest no. that divides all three
107 = 1×107
143 = 1×11×13
104 = 1×2×2×3×7
so the answer is 1
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