Find the largest number that will divide 260, 720, and 145 leaving 7 as remainder in each case
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Hi friend
Here's your answer looking for
First subtract the respective reminder from the given number.
260-7=253
720-7=713
And,
145-7=138
Now let's find the HCF of 253 713 and 138.
253= 11×23
713=23×31
And,138= 2×3×23
So, HCF = 23
Hence 23 is required number
Hope you are satisfied with my answer
Here's your answer looking for
First subtract the respective reminder from the given number.
260-7=253
720-7=713
And,
145-7=138
Now let's find the HCF of 253 713 and 138.
253= 11×23
713=23×31
And,138= 2×3×23
So, HCF = 23
Hence 23 is required number
Hope you are satisfied with my answer
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