Find the largest number that will divide 398,436,542, leaving remainder 7,11,15 respectively?
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3
Answer:
17
Step-by-step explanation:
398 - 7 = 391
436 - 11 = 425
542 - 15 = 527
we need to find out the HCF of 391, 425 and 527
391 = 17 × 23
425 = 17 × 25
527 = 17 × 31
the HCF of 391, 425 and 527 is 17
therefore the largest number that divides 398, 436 and 542 leaving remainder 7, 11, and 15 respectively is 17
hope you get your answer
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