Question

Find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11, and 15 respectively.

Answer 1

Answer:

below is the answer

Step-by-step explanation:

Algorithm

398 – 7 = 391, 436 – 11 = 425, 542 – 15 = 527

HCF of 391, 425, 527 = 17

Answer 2

Answer:

•Deducting the remainders from numbers we get,

→398−7=391

→436−11=425

→542−15=527

•H.C.F of these new numbers is the largest possible number that divides 398,436,542 leaving respective remainders

→391=17×23

→425=17×5²

→527=17×31

•Answer = H.C.F(391,425,527)=17

$\huge \green{ \boxed{ \sf \therefore 17 }}$