Math, asked by maneeshmanuchennitha, 10 months ago

find the largest number that will divide 398,436 and 542 leaving remainders 7,11 and 15 respectively

Answers

Answered by ornitho118

The answer to the question is 17.

Attachments:

maneeshmanuchennitha: thanks buddy.

maneeshmanuchennitha: can please explain more. it will be a help

ornitho118: We have to subtract the remainders to obtain the three numbers, it should be seen that correct remainders are subtracted from correct numbers. Then we have to find the GCD of the three numbers. Then we will find the three required numbers.

ornitho118: Hope you find this useful.

Answered by Anonymous

Given :-

398 , 436 and 542

To Find :-

The largest number

Solution :-

Let’s assume the integer is x

According to the condition given in the question

⇒ xy+7 = 398

⇒ xz+11 = 436

⇒ xk+15 = 542

⇒ xy =391

⇒ xz = 425

⇒ xk = 527

⇒ 17 × 23 = 391

⇒ 17 × 25 = 425

⇒ 17 × 31 = 527

So, the largest possible integer that will divide 398,436,542 & leaves reminder 7,11 and 15 respectively was 17.

Previous Question

Next Question

find the largest number that will divide 398,436 and 542 leaving remainders 7,11 and 15 respectively​

Answers

find the largest number that will divide 398,436 and 542 leaving remainders 7,11 and 15 respectively