find the largest number that will divide 398,436 and 542 leaving remainders 7,11 and 15 respectively
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Answered by
1
The answer to the question is 17.
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maneeshmanuchennitha:
thanks buddy.
can please explain more. it will be a help
We have to subtract the remainders to obtain the three numbers, it should be seen that correct remainders are subtracted from correct numbers. Then we have to find the GCD of the three numbers. Then we will find the three required numbers.
Hope you find this useful.
Answered by
4
Given :-
398 , 436 and 542
To Find :-
The largest number
Solution :-
Let’s assume the integer is x
According to the condition given in the question
⇒ xy+7 = 398
⇒ xz+11 = 436
⇒ xk+15 = 542
⇒ xy =391
⇒ xz = 425
⇒ xk = 527
⇒ 17 × 23 = 391
⇒ 17 × 25 = 425
⇒ 17 × 31 = 527
So, the largest possible integer that will divide 398,436,542 & leaves reminder 7,11 and 15 respectively was 17.
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