Question

Find the largest number that will divide 399, 440 and 550 leaving remainder 8, 15 and 23 respectively​

Answer 1

Step-by-step explanation:

Which is the largest number that will divide 399, 440 and 550 leaving remainders of 8, 15 and 23, respectively?

550–23 = 527.18

Answer 2

QUESTION:

• Find the largest number that will divide 399, 440 and 550 leaving remainder 8, 15 and 23 respectively

ANSWER:

Which is the largest number that will divide 399, 440 and 550 leaving remainders of 8, 15 and 23, respectively?

399–8 = 391

440-15 = 425

550–23 = 527.

Next find the factors of 391, 425 and 527.

391 = 17x23

425 = 5x5x17

527 = 17x31

The HCF is thus 17.

399/17 = 23 (Q) + 8 (R)

440/17 = 25 (Q) + 15 (R)

550/17 = 32 (Q) + 6 (R)

NOTE:

The question is wrong. Instead of 23 it should have been 6 as a remainder. [23/17 gives 1 (Q) and 6 (R)].