find the largest number that will divide 789, 861 and 1069 leaving remainders 7, 11 and 15 respectively
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Answered by
4
Largest number to divide can otherwise be explained as HCF
Since remainders are present we will subtract it from the numbers
Therefore
789-7= 782
861-11= 850
1069-15= 1054
HCF of these 3 no’s are 2*17= 34
Since remainders are present we will subtract it from the numbers
Therefore
789-7= 782
861-11= 850
1069-15= 1054
HCF of these 3 no’s are 2*17= 34
Answered by
5
Answer:
=34
Step-by-step explanation:
Subtracting the 7,11 and 15 from 789,861 and 1069 respectively
789-7=782
861-11=850
1069-15=1054
Now Taking factors of 782,850 and 1054
as per attachment
782 =2 x 17 x 23
850=2 x 5x 5 x 17
1054=2 x 17 x 31
Hence HCF of 782,850 and 1054 will be
=2x17=34
Therefore largest number that will divide 789, 861 and 1069 leaving remainders 7, 11 and 15 respectively
=34
782
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