Math, asked by swatipmulye, 1 year ago

Find the largest number that will divide 98, 36 and 42 leaving remainder 5 in each case.

Answers

Answered by maejor
0

Answer:

brainliest...

Step-by-step explanation:

soln: 98–5= 93

36–5= 31

41–5=36

here, a=91, b=31

use Euclid's division,

93= 31×3+0

hcf =3

now,

take a=36, b=3

36=3×12+0

hcf= 3

hence largest number is 3

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