find the largest number that will we divide 398,436and 542 leaving the remainder 7,11and 15 respectively
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Answer:
Deducting the remainders from numbers we get,
398−7=391
436−11=425
542−15=527
H.C.F of these new numbers is the largest possible number that divides 398,436,542 leaving respective remainders
391=17×23
425=17×5
2
527=17×31
∴ Answer = H.C.F(391,425,527)=17
I hope so this answer is helpful for you.
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Answer:
we can say that the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively is 17.
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