Question

Find the largest number the divides 621 and 969 leaving the remaider of 12 in each case​

Answer 1

Given,

Numbers = 621 , 969 leaves remainder 12

So,

new numbers = 621-12, 969-12

=609, 957

By division algorithm, Clearly 957 > 621

The HCF will be

87 Ans

Answer 2

Step-by-step explanation:

first subtract 12 from both

we get 609 and 957

then make hcf 609=29×7×3

and 957=29×11×3

hence coomon factors are 29×3=87

is largest no.