Find the largest number which can divide 70 and 125 and leaves remainer 5 and 8
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Remainder obtained on dividing 70 and 125= 5 and 8
So, (70-5) and (125-8) will be completely divisible.
(70-5)=65
(125-8)=117
H.C.F. of 65 and 117= 13.
Therefore, 13 is the required number.
So, (70-5) and (125-8) will be completely divisible.
(70-5)=65
(125-8)=117
H.C.F. of 65 and 117= 13.
Therefore, 13 is the required number.
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