Question

find the largest number which divided 245,405 and 1029 leaving 5 as remainder in each case

Answer 1

We will subtract 5 from 245, 405 and 1029


⛬ 245 - 5 = 240

405 - 5 = 400

1029 - 5 = 1024


Now, we will find the HCF of the obtained numbers i.e. 240, 400 and 1024


240 = 2 × 2 × 2 × 2 × 3 × 5

400 = 2 × 2 × 2 × 2 × 5 × 5

1029 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2


Common factors = 2 × 2 × 2 × 2

= 16


⛬ The HCF of 240, 400 and 1024 is 16.


⛬ The number is 16

Answer 2

❤❤Here is your answer ✌ ✌

$\huge\underline {\red {\bold {Answer}}}$


firstly subtract 5 from 245,405 and 1029

245-5=240
405-5=400
1029-5=1025

now factorise


240=2×2×2×2×3×5

405=2×2×2×2×5×5

1029=2×2×2×2×2×2×2×2×2×2

here common factor in( 240,405,1029)=2×2×2×2=16

so ,hence
hcf(240,405,1029)=16