find the largest number which divides 105band 150 leaving remainder 7 and 10 respectively
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As the largest positive integer that will divide 122, 150 and 115 leaves remainder 5, 7 and 11 respectively.
Therefore,
122−5=117
150−7=143
115−11=104
∵ The HCF of 104, 117 and 143 is 13
Hence, the largest number which divides 122, 150 and 115 leaving 5, 7 and 11 as remainders respectively is 13.
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