Find the largest number which divides 129,226,323 leaving remainder 1,2,3 respectively
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Answer:
Step-by-step explanation:
129 - 1 = 128
226 - 2 = 224
323 - 3 = 320
Hcf of 128 n 224
224 = 128 ×1. + 96
128 = 96 × 1 + 32
96 = 32 × 3 + 0
Hcf= 32
Greatest no. leaving these remainders is 32
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