Question

find the largest number which divides 146,254 and 272 leaving a remainder 2 in each case.​

Answer 1

Answer:

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Step-by-step explanation:

First you subtract 2 from each value.

144, 252 and 270.

Now you work out the prime factorization of each number.

.......144

....../.....\

...12.....12

.../..\..../...\

..3...4..3...4

....../..\..../..\

.....2...2..2...2

144 = 2^4 * 3^2

with the same method you can work out that:

252 = 2^2 * 3^2 *7

270 = 2 * 3^3 * 5

Now you look for common prime factors in each of the values: All of them shares a 2 and two 3s.

2*3*3 = 18

The answer is 18 :)

Answer 2

Step-by-step explanation:

first you have to subtract 2 from each case.

144,252,270.

And then find the HCF of the new numbers found.

HCF=18

for verification divide all the real numbers I. e. 146,254,272 with 18 you will found that it is leaving remainder 2 in each case

Hope it is helpful

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