find the largest number which divides 220, 313 and 716 leaving remainder 3 in each cases
Answers
Answered by
219
First we will subtract 3 from each no.-
220 - 3 = 217
313 - 3 = 310
716 - 3 = 713
Then, we will find the HCF of 217,310,713
217 = 7*31
310 = 2*5*31
713 = 23*31.
So, the HCF of 217,310,713 is 31.
So, therefore, the largest no. that divides 220,313, and 716 is 31.
Hope it helped you!!!
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220 - 3 = 217
313 - 3 = 310
716 - 3 = 713
Then, we will find the HCF of 217,310,713
217 = 7*31
310 = 2*5*31
713 = 23*31.
So, the HCF of 217,310,713 is 31.
So, therefore, the largest no. that divides 220,313, and 716 is 31.
Hope it helped you!!!
Please mark it as brainliest if you liked it!!
Answered by
45
Step 1
Subtract 3 from each number
220 - 3 = 217
313 - 3 = 310
716 - 3 = 713
Step 2
Find the HCF of 217,310
HCF = 31
Step 3
Find HCF of 31,713
HCF = 31 (Ans)
Answered by
27
Step 1
Subtract 3 from each number
220 - 3 = 217
313 - 3 = 310
716 - 3 = 713
Step 2
Find the HCF of 217,310
HCF = 31
Step 3
Find HCF of 31,713
HCF = 31 (Ans)
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